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A simple way of testing whether there is any significant association between household type in 1991 and living in a communal establishment in 2001 is a chi square test. This test is performed on a crosstabulation of two variables. In order to focus on our question, we need to simplify our table so that in 2001 we only measure residence in a private household versus residence in a communal establishment (otherwise other types of transition would affect the test).
| Living arrangement in 2001 by household type by 1991, residents in private households aged 65 or over in 1991 (%) | ||||||
|
Household type 1991 |
||||||
|
Living arrangement 2001 |
One person |
Couple only |
Couple plus other(s) |
Lone parent plus other(s) inc. offspring |
Other |
Total |
|
Private household |
86.8 | 95.1 |
97.6 |
92.6 |
87.9 |
92.2 |
|
Communal establishment |
13.2 |
4.9 |
2.4 |
7.4 |
12.1 |
7.8 |
| Total | 100 | 100 |
100 |
100 |
100 |
100 |
Pearson chi2 (4 d.f.)
= 824.8149, pr = 0.0000
The chi square value is very high at 824.8 and statistically significant
well below the 0.001 level. There is good reason to believe that entering
a communal establishment is associated with type of household.
| Command to create chi square statistic | |
| Where livarr01 is residence in private household or CE in 2001 and hhtype91 is household type in 1991. | |
| STATA | tab livarr01 hhtype91, col nofreq chi2 |
| SPSS |
crosstabs /tables livarr01 by hhtype91 /cells=col /stat=chisq. |
| SAS |
proc freq data=dataname; (where dataname is the name of the dataset) table livarr01*hhtype91 /chisq; |
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